Integrand size = 30, antiderivative size = 17 \[ \int (d+e x)^2 \left (c d^2+2 c d e x+c e^2 x^2\right )^2 \, dx=\frac {c^2 (d+e x)^7}{7 e} \]
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Time = 0.00 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {27, 12, 32} \[ \int (d+e x)^2 \left (c d^2+2 c d e x+c e^2 x^2\right )^2 \, dx=\frac {c^2 (d+e x)^7}{7 e} \]
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Rule 12
Rule 27
Rule 32
Rubi steps \begin{align*} \text {integral}& = \int c^2 (d+e x)^6 \, dx \\ & = c^2 \int (d+e x)^6 \, dx \\ & = \frac {c^2 (d+e x)^7}{7 e} \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.00 \[ \int (d+e x)^2 \left (c d^2+2 c d e x+c e^2 x^2\right )^2 \, dx=\frac {c^2 (d+e x)^7}{7 e} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(68\) vs. \(2(15)=30\).
Time = 2.47 (sec) , antiderivative size = 69, normalized size of antiderivative = 4.06
method | result | size |
gosper | \(\frac {x \left (e^{6} x^{6}+7 d \,e^{5} x^{5}+21 d^{2} e^{4} x^{4}+35 x^{3} d^{3} e^{3}+35 d^{4} e^{2} x^{2}+21 d^{5} e x +7 d^{6}\right ) c^{2}}{7}\) | \(69\) |
default | \(\frac {1}{7} e^{6} c^{2} x^{7}+d \,e^{5} c^{2} x^{6}+3 d^{2} e^{4} c^{2} x^{5}+5 d^{3} c^{2} e^{3} x^{4}+5 d^{4} c^{2} e^{2} x^{3}+3 d^{5} e \,c^{2} x^{2}+d^{6} c^{2} x\) | \(86\) |
norman | \(\frac {1}{7} e^{6} c^{2} x^{7}+d \,e^{5} c^{2} x^{6}+3 d^{2} e^{4} c^{2} x^{5}+5 d^{3} c^{2} e^{3} x^{4}+5 d^{4} c^{2} e^{2} x^{3}+3 d^{5} e \,c^{2} x^{2}+d^{6} c^{2} x\) | \(86\) |
risch | \(\frac {1}{7} e^{6} c^{2} x^{7}+d \,e^{5} c^{2} x^{6}+3 d^{2} e^{4} c^{2} x^{5}+5 d^{3} c^{2} e^{3} x^{4}+5 d^{4} c^{2} e^{2} x^{3}+3 d^{5} e \,c^{2} x^{2}+d^{6} c^{2} x\) | \(86\) |
parallelrisch | \(\frac {1}{7} e^{6} c^{2} x^{7}+d \,e^{5} c^{2} x^{6}+3 d^{2} e^{4} c^{2} x^{5}+5 d^{3} c^{2} e^{3} x^{4}+5 d^{4} c^{2} e^{2} x^{3}+3 d^{5} e \,c^{2} x^{2}+d^{6} c^{2} x\) | \(86\) |
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Leaf count of result is larger than twice the leaf count of optimal. 85 vs. \(2 (15) = 30\).
Time = 0.27 (sec) , antiderivative size = 85, normalized size of antiderivative = 5.00 \[ \int (d+e x)^2 \left (c d^2+2 c d e x+c e^2 x^2\right )^2 \, dx=\frac {1}{7} \, c^{2} e^{6} x^{7} + c^{2} d e^{5} x^{6} + 3 \, c^{2} d^{2} e^{4} x^{5} + 5 \, c^{2} d^{3} e^{3} x^{4} + 5 \, c^{2} d^{4} e^{2} x^{3} + 3 \, c^{2} d^{5} e x^{2} + c^{2} d^{6} x \]
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Leaf count of result is larger than twice the leaf count of optimal. 90 vs. \(2 (12) = 24\).
Time = 0.02 (sec) , antiderivative size = 90, normalized size of antiderivative = 5.29 \[ \int (d+e x)^2 \left (c d^2+2 c d e x+c e^2 x^2\right )^2 \, dx=c^{2} d^{6} x + 3 c^{2} d^{5} e x^{2} + 5 c^{2} d^{4} e^{2} x^{3} + 5 c^{2} d^{3} e^{3} x^{4} + 3 c^{2} d^{2} e^{4} x^{5} + c^{2} d e^{5} x^{6} + \frac {c^{2} e^{6} x^{7}}{7} \]
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Leaf count of result is larger than twice the leaf count of optimal. 85 vs. \(2 (15) = 30\).
Time = 0.19 (sec) , antiderivative size = 85, normalized size of antiderivative = 5.00 \[ \int (d+e x)^2 \left (c d^2+2 c d e x+c e^2 x^2\right )^2 \, dx=\frac {1}{7} \, c^{2} e^{6} x^{7} + c^{2} d e^{5} x^{6} + 3 \, c^{2} d^{2} e^{4} x^{5} + 5 \, c^{2} d^{3} e^{3} x^{4} + 5 \, c^{2} d^{4} e^{2} x^{3} + 3 \, c^{2} d^{5} e x^{2} + c^{2} d^{6} x \]
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Leaf count of result is larger than twice the leaf count of optimal. 85 vs. \(2 (15) = 30\).
Time = 0.27 (sec) , antiderivative size = 85, normalized size of antiderivative = 5.00 \[ \int (d+e x)^2 \left (c d^2+2 c d e x+c e^2 x^2\right )^2 \, dx=\frac {1}{7} \, c^{2} e^{6} x^{7} + c^{2} d e^{5} x^{6} + 3 \, c^{2} d^{2} e^{4} x^{5} + 5 \, c^{2} d^{3} e^{3} x^{4} + 5 \, c^{2} d^{4} e^{2} x^{3} + 3 \, c^{2} d^{5} e x^{2} + c^{2} d^{6} x \]
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Time = 0.04 (sec) , antiderivative size = 85, normalized size of antiderivative = 5.00 \[ \int (d+e x)^2 \left (c d^2+2 c d e x+c e^2 x^2\right )^2 \, dx=c^2\,d^6\,x+3\,c^2\,d^5\,e\,x^2+5\,c^2\,d^4\,e^2\,x^3+5\,c^2\,d^3\,e^3\,x^4+3\,c^2\,d^2\,e^4\,x^5+c^2\,d\,e^5\,x^6+\frac {c^2\,e^6\,x^7}{7} \]
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